JAVA 五子棋 判断输赢的代码实现

<pre name="code" class="java">//定义棋盘大小，宽w，高hint w = 11;int h = w;//用一个二维数组保存棋盘数据，1代表红棋，2代表黑棋int[][] chess = new int[h][w];//定义控制循环的布尔变量boolean game_over = false;boolean win_red = false;boolean win_black = false;

//判断输赢的函数，传入当前点位置坐标public void judge(int y3, int x3) {//创建4个StringBuffer对象分别保存横向，纵向，两个斜向棋盘数据StringBuffer buf21 = new StringBuffer();StringBuffer buf14 = new StringBuffer();StringBuffer buf13 = new StringBuffer();StringBuffer buf24 = new StringBuffer();// 横向数据流for (int y = y3, x = 0; x < w; x++) {buf21.append(chess[y][x]);}//System.out.println(buf21);// 纵向数据流for (int y = 0, x = x3; y < h; y++) {buf14.append(chess[y][x]);}//System.out.println(buf14);// 二四象限数据流if (y3 >= x3) {for (int y = y3 - x3, x = 0; y < h; y++, x++) {buf24.append(chess[y][x]);}} else {for (int y = 0, x = x3 - y3; x < w; y++, x++) {buf24.append(chess[y][x]);}}//System.out.println(buf24);// 一三象限数据流if ((x3 + y3) < h) {for (int x = x3 + y3, y = 0; y <= x3 + y3; y++, x--) {buf13.append(chess[y][x]);}} else {for (int x = h - 1, y = x3 + y3 - (h - 1); y < h; y++, x--) {buf13.append(chess[y][x]);}}//System.out.println(buf13);//使用正则表达式匹配数据判断输赢，连续5个1表示红棋赢，连续5个二表示黑棋赢if (buf21.toString().matches("\\d*1{5}\\d*")|| buf14.toString().matches("\\d*1{5}\\d*")|| buf13.toString().matches("\\d*1{5}\\d*")|| buf24.toString().matches("\\d*1{5}\\d*")) {win_red =true;}if (buf21.toString().matches("\\d*2{5}\\d*")|| buf14.toString().matches("\\d*2{5}\\d*")|| buf13.toString().matches("\\d*2{5}\\d*")|| buf24.toString().matches("\\d*2{5}\\d*")) {win_black =true;}if (win_red) {JOptionPane.showMessageDialog(null, "红棋赢！");} else if (win_black) {JOptionPane.showMessageDialog(null, "黑棋赢！");}}