C语言 经典练习 输出当前时间的下一秒

输出当前的时间的下一秒 C 语言实现！

#include <stdio.h>#include <stdlib.h>#include <conio.h>enum DateType{    YEAR,    MONTH,    DAY,    HOUR,    MINUTE,    SEC,    MAX,};#define DUMMY 0const char *g_apcCnName[MAX]={"年","月","日","时","分","秒"};int isLeapYear(int iYear){    return ((iYear%4==0&&iYear%100!=0)||iYear%400==0);}int main(){    int i;    int aiTime[MAX]={0};    int aiTimeMaxValue[MAX]={9999,12,31,23,59,59};    int aiTimeMinValue[MAX]={1970,1,1,0,0,0,};    int aiMonthMaxDay[]={DUMMY,31,28,31,30,31,30,31,31,30,31,30,31};    for(i=YEAR;i<MAX;++i)    {        printf("请输入%s",g_apcCnName[i]);        scanf("%d",aiTime+i);        if(MONTH==i&&isLeapYear(aiTime[YEAR]))        {            aiMonthMaxDay[2]=29;        }        if(DAY==i)        {          aiTimeMaxValue[DAY]=aiMonthMaxDay[aiTime[MONTH]];        }        if(aiTime[i]>aiTimeMaxValue[i]||aiTime[i]<aiTimeMinValue[i])        {            printf("输入数据不合法,请重新输入\n");            i--;        }    }    aiTime[SEC]++;    for(i=SEC;i>YEAR;i--)    {        if(aiTime[i]>aiTimeMaxValue[i])        {            aiTime[i]=aiTimeMinValue[i];            aiTime[i-1]++;        }    }    printf("\n最后的输出结果是：");    for(i=YEAR;i<MAX;i++)    {        printf("%d%s",aiTime[i],g_apcCnName[i]);    }    getch();    return 0;}