Java Insert Interval(插入间隔)

来源：互联网发布：什么是移动数据流量编辑：程序博客网时间：2024/05/22 00:06

Problem:

Given a set of non-overlapping & sorted intervals, insert a new interval into the intervals (merge if necessary).
Example 1:Given intervals [1,3],[6,9], insert and merge [2,5] in as [1,5],[6,9].Example 2:Given [1,2],[3,5],[6,7],[8,10],[12,16], insert and merge [4,9] in as [1,2],[3,10],[12,16].This is because the new interval [4,9] overlaps with [3,5],[6,7],[8,10].

Thoughts of This Problem

Quickly summarize 3 cases. Whenever there is intersection, created a new interval.

Java Solution

/** * Definition for an interval. * public class Interval { *     int start; *     int end; *     Interval() { start = 0; end = 0; } *     Interval(int s, int e) { start = s; end = e; } * } */public class Solution {    public ArrayList<Interval> insert(ArrayList<Interval> intervals, Interval newInterval) {         ArrayList<Interval> result = new ArrayList<Interval>();         for(Interval interval: intervals){            if(interval.end < newInterval.start){                result.add(interval);            }else if(interval.start > newInterval.end){                result.add(newInterval);                newInterval = interval;                    }else if(interval.end >= newInterval.start || interval.start <= newInterval.end){                newInterval = new Interval(Math.min(interval.start, newInterval.start), Math.max(newInterval.end, interval.end));            }        }         result.add(newInterval);          return result;    }}

0 0