HDOJ 1012 u Calculate e

u Calculate e

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 29875    Accepted Submission(s): 13312

Problem Description

A simple mathematical formula for e is



where n is allowed to go to infinity. This can actually yield very accurate approximations of e using relatively small values of n.

 

Output

Output the approximations of e generated by the above formula for the values of n from 0 to 9. The beginning of your output should appear similar to that shown below.

 

Sample Output

n e- -----------0 11 22 2.53 2.6666666674 2.708333333

 

#include<stdio.h>int main(){int n,i;double e=2.5,s=2;printf("n e\n");printf("- -----------\n"); for(i=0;i<10;i++){if(i==0)  printf("0 1\n"); if(i==1)  printf("1 2\n"); if(i==2)  printf("2 2.5\n");if(i>2){s=s*i;e=e+(double)(1/s);printf("%d %.9lf\n",i,e);}}return 0;}