ural 1880. Psych Up's Eigenvalues
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题意:找出三个数组中相同的数字的个数
代码如下:
#include<cstdio>#include<iostream>#include<cstring>using namespace std;int num[3][4005];int sav[4005];int top=0;int main(){// freopen("data.txt","r",stdin); int n[3]; scanf("%d",&n[0]); for(int i=0;i<n[0];++i) { scanf("%d",&num[0][i]); } scanf("%d",&n[1]); int it=0; for(int i=0;i<n[1];++i) { scanf("%d",&num[1][i]); for(;it<n[0];++it) { if(num[0][it]==num[1][i]){sav[top++]=num[1][i];break;} if(num[0][it]>num[1][i])break; } } scanf("%d",&n[2]); int ans=0; it=0; for(int i=0;i<n[2];++i) { scanf("%d",&num[2][i]); for(;it<top;++it) { if(sav[it]==num[2][i]){ ans++;break; } if(sav[it]>num[2][i])break; } } printf("%d\n",ans); return 0;}
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