【TOJ 2911】 Deli Deli【水题】

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水题一枚。

题目大意：按照题目要求将所给单词转化为复数形式。

#include <iostream>#include <map>#include <cstring>using namespace std;int main(){    map<string, string>M;    map<char, int>S;    int l,n;    S['a'] = 1, S['e'] = 1;    S['i'] = 1, S['o'] = 1, S['u'] = 1;    string s[102];    string a, b;    while (cin >> l >> n)    {          M.clear();          while (l--)          {                cin >> a >> b;                M[a] = b;          }          for (int i = 0;i < n;i++)          {                cin >> s[i];                if (M.find(s[i]) != M.end()) s[i] = M[s[i]];                else                {                    int len = s[i].length();                    switch (s[i][len - 1])                    {                       case 'y': if (len > 1 && (S.find(s[i][len - 2])) == S.end()) s[i][len - 1] = 'i', s[i] += "es";                                 else s[i] += "s";break;                       case 'o':                       case 's':                       case 'x':s[i] += "es";break;                       case 'h': if (len > 1 && (s[i][len - 2] == 'c' || s[i][len - 2] == 's'))                                    s[i] += "es";                                 else s[i] += "s";break;                       default:s[i] += "s";break;                    }                }          }          for (int i = 0;i < n;i++) cout << s[i] << endl;    }    return 0;}

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