hdu 1004 Let the Balloon Rise

Problem Description

Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.

This year, they decide to leave this lovely job to you.

 

Input

Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.

A test case with N = 0 terminates the input and this test case is not to be processed.

 

Output

For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.

 

Sample Input

5greenredblueredred3pinkorangepink0

 

Sample Output

redpink

 

 //对于这道题，没有明确规定又多个受欢迎的球怎么处理，只有默认输出最面一个

#include<stdio.h>#include<string.h> int main() {  int n,i,j,max,t;  char a[1010][20];  int b[1010];    while(scanf("%d",&n),n)  {  memset(b,0,sizeof(b)); //此处的memset要放在循环里面  for( i=0;i<n;i++)     scanf("%s",a[i]);        for(i=0;i<n;i++)   {   for(j=0;j<n;j++)          if(strcmp(a[i],a[j])==0) b[i]++;         }    max=b[0];     t=0;    for(i=0;i<n;i++)    {      if(max<b[i])       {       max=b[i];          t=i;       }      }    puts(a[t]);//puts()自动换行      }   return 0; }