2015 偶数求和

http://acm.hdu.edu.cn/showproblem.php?pid=2015

#include<stdio.h>int a[200];int main(){     int n,m,i,j,i_,j_,sum;     for(i_=0;i_<100;i_++)     {        a[i_]=(i_+1)*2;     }     while(scanf("%d %d",&n,&m)!=EOF)     {            for(i=0;i<n;i+=m)            {                    for(j=i,j_=0,sum=0;j<(i+m)&&j<n;j++,j_++)                    {                           sum+=a[j];                    }                    printf("%d",sum/j_);                    if((i+m)<n)                    printf(" ");                    //else                    //printf("#");            }            printf("\n");     }     return 0;}