Leetcode_Zig Zag Conversion

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<p style="box-sizing: border-box; margin-top: 0px; margin-bottom: 10px; color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 13.63636302947998px; line-height: 30px;">The string <code style="box-sizing: border-box; font-family: Monaco, Menlo, Consolas, 'Courier New', monospace; font-size: 12.727272033691406px; padding: 2px 4px; color: rgb(199, 37, 78); white-space: nowrap; background-color: rgb(249, 242, 244); border-top-left-radius: 4px; border-top-right-radius: 4px; border-bottom-right-radius: 4px; border-bottom-left-radius: 4px;">"PAYPALISHIRING"</code> is written in a zigzag pattern on a given number of rows like this: (you may want to display this pattern in a fixed font for better legibility)</p><pre style="box-sizing: border-box; font-family: Monaco, Menlo, Consolas, 'Courier New', monospace; font-size: 13px; white-space: pre-wrap; padding: 9.5px; margin-top: 0px; margin-bottom: 10px; line-height: 1.428571429; color: rgb(51, 51, 51); word-break: break-all; word-wrap: break-word; background-color: rgb(245, 245, 245); border: 1px solid rgb(204, 204, 204); border-top-left-radius: 4px; border-top-right-radius: 4px; border-bottom-right-radius: 4px; border-bottom-left-radius: 4px;">P   A   H   NA P L S I I GY   I   R

And then read line by line: "PAHNAPLSIIGYIR"

Write the code that will take a string and make this conversion given a number of rows:

string convert(string text, int nRows);

convert("PAYPALISHIRING", 3) should return "PAHNAPLSIIGYIR".

<span style="color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 13.63636302947998px; line-height: 30px;">解题方法：</span>

<span style="color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 13.63636302947998px; line-height: 30px;">该题没有什么特别之处，纯粹提取规律+跳出循环条件考虑</span>

<span style="color: rgb(51, 51, 51); font-family: 'Helvetica Neue', Helvetica, Arial, sans-serif; font-size: 13.63636302947998px; line-height: 30px;"></span>

string convert(string s, int nRows) {if(nRows == 1)return s;string ans  = s;int k = 2*(nRows-1);int index = 0;for(int i = 0; i < nRows; ++i){int increment = k - 2*i;int currentindex = i;while(currentindex < s.size()){if(increment != 0){ans[index] = s[currentindex];++index;}currentindex += increment;increment = k - increment;}}return ans;}

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