北大暑假训练计划—POJ2105 IP Address(C语言)
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IP Address
Description
Suppose you are reading byte streams from any device, representing IP addresses. Your task is to convert a 32 characters long sequence of '1s' and '0s' (bits) to a dotted decimal format. A dotted decimal format for an IP address is form by grouping 8 bits at a time and converting the binary representation to decimal representation. Any 8 bits is a valid part of an IP address. To convert binary numbers to decimal numbers remember that both are positional numerical systems, where the first 8 positions of the binary systems are:
27 26 25 24 23 22 21 20
128 64 32 16 8 4 2 1
Input
The input will have a number N (1<=N<=9) in its first line representing the number of streams to convert. N lines will follow.
Output
The output must have N lines with a doted decimal IP address. A dotted decimal IP address is formed by grouping 8 bit at the time and converting the binary representation to decimal representation.
Sample Input
4
00000000000000000000000000000000
00000011100000001111111111111111
11001011100001001110010110000000
01010000000100000000000000000001
Sample Output
0.0.0.0
3.128.255.255
203.132.229.128
80.16.0.1
#include<stdio.h>
#include<string.h>
int main()
{
int i,a,b,c,d,n;
char s[40];
scanf("%d",&n);
getchar();
while(n--)
{
gets(s);//输入后面可以有空格,所以数组开的比32大一点才可以,而且要用ges()输入,才可以输入空格
a=0;
b=0;
c=0;
d=0;
for(i=0;i<32;i++)
{
if(i/8==0)
{
a=a*2+(s[i]-'0');
}
else if(i/8==1)
{
b=b*2+(s[i]-'0');
}
else if(i/8==2)
{
c=c*2+(s[i]-'0');
}
else if(i/8==3)
{
d=d*2+(s[i]-'0');
}
}
printf("%d.%d.%d.%d\n",a,b,c,d);
}
return 0;
}
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