hd 1720 A+B Coming

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A+B Coming

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 5501 Accepted Submission(s): 3601

Problem Description

Many classmates said to me that A+B is must needs.
If you can’t AC this problem, you would invite me for night meal. ^_^

Input

Input may contain multiple test cases. Each case contains A and B in one line.
A, B are hexadecimal number.
Input terminates by EOF.

Output

Output A+B in decimal number in one line.

Sample Input

1 9A Ba b

Sample Output

Author

威士忌

Source

HZIEE 2007 Programming Contest

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#include<stdio.h>

int main()
{
int n,m;
while(scanf("%x%x",&m,&n)!=EOF)
{
printf("%d\n",m+n);
}
return 0;

}

%a,%A 读入一个浮点值(仅C99有效) 　　%c 读入一个字符 　　%d 读入十进制整数 　　%i 读入十进制，八进制，十六进制整数 　　%o 读入八进制整数 　　%x,%X 读入十六进制整数 　　%s 读入一个字符串，遇空格、制表符或换行符结束。 　　%f,%F,%e,%E,%g,%G 用来输入实数，可以用小数形式或指数形式输入。 　　%p 读入一个指针 　　%u 读入一个无符号十进制整数 　　%n 至此已读入值的等价字符数 　　%[] 扫描字符集合 　　%% 读%符号

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