杭电Let the Balloon Rise
来源:互联网 发布:冰与火之歌第七季 知乎 编辑:程序博客网 时间:2024/05/19 00:42
Let the Balloon Rise
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 73536 Accepted Submission(s): 27466
Problem Description
Contest time again! How excited it is to see balloons floating around. But to tell you a secret, the judges' favorite time is guessing the most popular problem. When the contest is over, they will count the balloons of each color and find the result.
This year, they decide to leave this lovely job to you.
This year, they decide to leave this lovely job to you.
Input
Input contains multiple test cases. Each test case starts with a number N (0 < N <= 1000) -- the total number of balloons distributed. The next N lines contain one color each. The color of a balloon is a string of up to 15 lower-case letters.
A test case with N = 0 terminates the input and this test case is not to be processed.
A test case with N = 0 terminates the input and this test case is not to be processed.
Output
For each case, print the color of balloon for the most popular problem on a single line. It is guaranteed that there is a unique solution for each test case.
Sample Input
5greenredblueredred3pinkorangepink0
Sample Output
redpink#include<stdio.h>#include<string.h>int main(){int n,i,t,j;char s[1005][16];while(scanf("%d",&n)!=EOF&&n!=0){int count[1000]={0},max=0;getchar();//注意空格键的接收for(i=0;i<n;i++){gets(s[i]);//scanf遇见空格就不停止了}for(i=0;i<n;i++){if(s[i][0]=='\0')continue;for(j=i+1;j<n;j++){if(s[j][0]=='\0')continue;if(strcmp(s[i],s[j])==0){s[j][0]='\0';count[i]++;}}//从第一个元素开始找,如果相同把该字符串的第一个字符改为\0相当于标记该元素;if(max<count[i]){t=max;max=count[i];count[i]=t;t=i;}}puts(s[t]);}return 0;}
0 0
- 杭电 1004[Let the Balloon Rise]
- 杭电 1004 Let the Balloon Rise
- 杭电 1004 Let the Balloon Rise
- [杭电]Let the Balloon Rise
- 杭电Let the Balloon Rise
- 杭电 1004 Let the Balloon Rise
- 杭电1004 Let the Balloon Rise
- 杭电-1004 Let the Balloon Rise
- 杭电1004---Let the Balloon Rise
- 杭电1004-Let the Balloon Rise
- 杭电OJ Let the Balloon Rise
- 【杭电】 1004 Let the Balloon Rise
- 杭电 1004 Let the Balloon Rise
- 杭电problem1004- Let the Balloon Rise
- 杭电1004 Let the Balloon Rise
- Let the Balloon Rise(杭电ACM 1004)
- 杭电acm 1004 (Let the Balloon Rise)
- 杭电ACM 1004 “+Let+the+Balloon+Rise”
- perl语法总结
- jQuery 遍历 - 同胞
- 菜鸟进军c++(一)
- python 并发执行
- Heritage(高精度)
- 杭电Let the Balloon Rise
- oracle 通过with字句更新另一个表
- Android聊天表情开发
- 测试
- 情殷鉴古是什么意思
- Android Trick: 改变一个apk的packagename的简单流程,就2个步骤
- [HDU1158]DP 工厂雇佣决策
- linux 库编译和使用笔记
- linux基础知识之shell(2)