hdu 1250 Hat's Fibonacci
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Hat's Fibonacci
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 7492 Accepted Submission(s): 2428
Problem Description
A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.
Input
Each line will contain an integers. Process to end of file.
Output
For each case, output the result in a line.
Sample Input
100
Sample Output
4203968145672990846840663646Note:No generated Fibonacci number in excess of 2005 digits will be in the test data, ie. F(20) = 66526 has 5 digits.
#include <iostream>#include <cstring>using namespace std;string add(string a,string b){ string Max,Min; if(a.size()>b.size()) { Max=a; Min=b; } else { Max=b; Min=a; } long j=Max.size()-1; for (long i=Min.size()-1; i>=0; i--,j--) { Max[j]+=Min[i]-'0'; } for (j=Max.size()-1; j>=1; j--) { if(Max[j]>'9') { Max[j]-=10; Max[j-1]++; } } if(Max[0]>'9') { Max[0]-=10; Max='1'+Max; } return Max;}int main(){ string s[10000]; int n; s[1]='1'; s[2]='1'; s[3]='1'; s[4]='1'; for (int i=5; i<10000; i++) { s[i]=add(add(add(s[i-1], s[i-2]),s[i-3]),s[i-4]); } while(cin>>n) { cout<<s[n]<<endl; } return 0;}
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