SGU194 Reactor Cooling 有下界最大流
来源:互联网 发布:phpcms域名绑定目录 编辑:程序博客网 时间:2024/05/20 10:52
学习别人的方法。大致是:
无源汇的最大流 : 新建源点,汇点,sum[i]为每个点进来的下界流之和减去出去的下界流之和,如果sum[i] > 0,由源点向该点建一条边,上界为sum[i],下界为0
如果sum[i] < 0, 由该点向汇点建边,上界为-sum[i],下界为0。
跑一遍源点到汇点的最大流,当所有源点连得边都满流的时候存在可行流,当前的流量即为最大流。
#include <cstdio>#include <ctime>#include <cstdlib>#include <cstring>#include <queue>#include <string>#include <set>#include <stack>#include <map>#include <cmath>#include <vector>#include <iostream>#include <algorithm>#include <bitset>#include <fstream>using namespace std;//LOOP#define FF(i, a, b) for(int i = (a); i < (b); ++i)#define FE(i, a, b) for(int i = (a); i <= (b); ++i)#define FED(i, b, a) for(int i = (b); i>= (a); --i)#define REP(i, N) for(int i = 0; i < (N); ++i)#define CLR(A,value) memset(A,value,sizeof(A))#define FC(it, c) for(__typeof((c).begin()) it = (c).begin(); it != (c).end(); it++)//OTHER#define SZ(V) (int)V.size()#define PB push_back#define MP make_pair#define all(x) (x).begin(),(x).end()//INPUT#define RI(n) scanf("%d", &n)#define RII(n, m) scanf("%d%d", &n, &m)#define RIII(n, m, k) scanf("%d%d%d", &n, &m, &k)#define RIV(n, m, k, p) scanf("%d%d%d%d", &n, &m, &k, &p)#define RV(n, m, k, p, q) scanf("%d%d%d%d%d", &n, &m, &k, &p, &q)#define RS(s) scanf("%s", s)//OUTPUT#define WI(n) printf("%d\n", n)#define WS(n) printf("%s\n", n)//debug//#define online_judge#ifndef online_judge#define dt(a) << (#a) << "=" << a << " "#define debugI(a) cout dt(a) << endl#define debugII(a, b) cout dt(a) dt(b) << endl#define debugIII(a, b, c) cout dt(a) dt(b) dt(c) << endl#define debugIV(a, b, c, d) cout dt(a) dt(b) dt(c) dt(d) << endl#define debugV(a, b, c, d, e) cout dt(a) dt(b) dt(c) dt(d) dt(e) << endl#else#define debugI(v)#define debugII(a, b)#define debugIII(a, b, c)#define debugIV(a, b, c, d)#endif#define sqr(x) (x) * (x)typedef long long LL;typedef unsigned long long ULL;typedef vector <int> VI;const double eps = 1e-9;const int MOD = 1000000007;const double PI = acos(-1.0);const int INF = 0x3f3f3f3f;const int maxn = 100010;struct Edge{ int from, to, cap, flow, lcap;};int n, m, s, t;vector<Edge> edges;VI G[maxn];bool vis[maxn];int d[maxn], cur[maxn];void init(){ REP(i, n + 1) G[i].clear(); edges.clear();}void addEdge(int from, int to, int cap, int lcap){ edges.PB((Edge){from, to, cap, 0, lcap}); edges.PB((Edge){to, from, 0, 0, -lcap}); m = edges.size(); G[from].PB(m - 2); G[to].PB(m - 1);}bool bfs(){ CLR(vis, 0); queue<int> Q; Q.push(s); d[s] = 0, vis[s] = 1; while (!Q.empty()) { int u = Q.front(); Q.pop(); REP(i, G[u].size()) { Edge& e = edges[G[u][i]]; if (!vis[e.to] && e.cap > e.flow) { vis[e.to] = 1; d[e.to] = d[u] + 1; Q.push(e.to); } } } return vis[t];}int dfs(int x, int a){ if (x == t || a == 0) return a; int flow = 0, f; for (int& i = cur[x];i < G[x].size(); i++) { Edge& e = edges[G[x][i]]; if (d[x] + 1 == d[e.to] && (f = dfs(e.to, min(a, e.cap - e.flow))) > 0) { e.flow += f; edges[G[x][i] ^ 1].flow -= f; flow += f; a -= f; if (a == 0) break; } } return flow;}int maxflow(int ss, int tt){ s = ss, t = tt; int flow = 0; while (bfs()) { CLR(cur, 0); flow += dfs(s, INF); } return flow;}int sum[maxn];int main(){ //freopen("0.txt", "r", stdin); int nodenum, edgenum; int u, v, l, c; int se, te; while (~RII(nodenum, edgenum)) { CLR(sum, 0); n = nodenum + 2; init(); REP(i, edgenum) { RIV(u, v, l, c); addEdge(u, v, c - l, l); sum[u] -= l; sum[v] += l; } se = edges.size(), te = se; FE(i, 1, nodenum) if (sum[i] > 0) addEdge(0, i, sum[i], 0), te = edges.size(); FE(i, 1, nodenum) if (sum[i] < 0) addEdge(i, nodenum + 1, -sum[i], 0); int maxf = maxflow(0, nodenum + 1);// debugI(maxf);// debugII(se, te); bool f = 0; for (int i = se; i < te; i += 2) if (edges[i].flow < edges[i].cap) { f = 1; break; } if (f) puts("NO"); else { puts("YES");// REP(i, edges.size()) for (int i = 0; i < se; i += 2) printf("%d\n", edges[i].flow + edges[i].lcap); } } return 0;}
6 2
- SGU194 Reactor Cooling 有下界最大流
- 最大流问题——无源汇有上下界最大流 sgu194 Reactor Cooling
- 【无源汇点上下界可行流】[SGU194]Reactor Cooling
- 【SGU194】Reactor Cooling 无源汇上下界可行流
- sgu194. Reactor Cooling 无源汇上下界可行流
- [ZOJ2314]/[SGU194] Reactor Cooling 无源汇有上下界网络流
- sgu194:Reactor Colling(无源无汇上下界最大流)
- zoj 2314 Reactor Cooling 有上下界的网络最大流
- zoj2314 Reactor Cooling (无源汇的有上下界的最大流)
- sgu 194 Reactor Cooling 无源汇有上下界最大流
- SGU 194. Reactor Cooling【无源汇上下界最大流】
- SGU - 194 Reactor Cooling(无源无汇有上下界最大流)
- SGU 194. Reactor Cooling (无源汇有上下界最大流
- SGU 194 Reactor Cooling(无源汇有上下界最大流)
- 【无源汇上下界最大流】SGU 194 Reactor Cooling
- sgu-194-Reactor Cooling(无源汇有上下界最大流)
- ZOJ2314 Reactor Cooling (有上下界的网络流)
- zoj 2314 Reactor Cooling (有上下界的网络流)
- hdu-oj 1076 An Easy Task
- dbgrideh 一个单元格内怎么换行显示
- 设置MyEclipse中.jsp .xml样式
- mount -t vboxsf Desktop /home/h/Desktop/windesktop 写到/etc/rc.d/rc.local里.
- UVA-120- Stacks of Flapjacks
- SGU194 Reactor Cooling 有下界最大流
- 黑马程序员 - 学习笔记8 接口的初步了解
- 学习笔记 Java_毕向东_创建线程_同步代码块synchronized 2014.8.6
- 深入理解Linux进程间通信(IPC)-- FIFO
- lda(linear discriminant analysis)线性判别分析算法代码
- 数据挖掘算法源代码:很好的参考资料
- 神交流:纯表情社交应用,能摆到桌面?
- HDU 4907 Task schedule(BestCoder Round #3 )
- Apache ab工具Nginx压力测试