LeetCode Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4

[1,3,5,6], 0 → 0

class Solution {public:int searchInsert(int A[], int n, int target) {return biSearch(A, 0, n - 1, target);}int biSearch(int A[], int L, int R, int target){if (R < L)return L;                          //注意返回的 是L， 代表应该插入的位置int mid = L + ((R - L) >> 1);if (A[mid] == target)return mid;else if (A[mid] > target)return biSearch(A, L, mid - 1, target);elsereturn biSearch(A, mid + 1, R, target);}};