LeetCode 109. Convert Sorted List to Binary Search Tree
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和LeetCode 108. Convert Sorted Array to Binary Search Tree
给定升序链表，构造平衡查找二叉树。
用slow, fast指针将链表分成两条即可。
代码：
class Solution {public: TreeNode *sortedListToBST(ListNode *head) { if (head == NULL) { return NULL; } ListNode *pre=NULL, *slow=head, *fast=head; while (fast->next!=NULL && fast->next->next!=NULL) { pre = slow; slow = slow->next; fast = fast->next->next; } TreeNode *tree = new TreeNode(slow->val); if (pre != NULL) { pre->next = NULL; tree->left = sortedListToBST(head); } else { tree->left = NULL; } tree->right = sortedListToBST(slow->next); return tree; }}; 0 0
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