opencv直方图拉伸

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1、首先计算出一幅图像的直方图

//计算直方图cv::MatND ImageHist::getHist(const cv::Mat &image){cv::Mat im;if(image.channels() == 3)cv::cvtColor(image,im,CV_RGB2GRAY,0);elseim = image;float r[2];r[0] = 0;r[1] = 255;const float *ranges[1];ranges[0] = r;cv::calcHist(&im,1,&channels,cv::Mat(),hist,1,&histSize,ranges);return hist;}//将直方图生成图像,以便在MFC空间中显示cv::Mat ImageHist::getHistImage(const cv::Mat &image){double maxVal = 0;double minVal = 0;cv::minMaxLoc(hist,&minVal,&maxVal,0,0);cv::Mat histImg(histSize,histSize,CV_8U,cv::Scalar(255));int high = histSize * 0.9;for (int i = 0;i < histSize;++i){float binVal = hist.at<float>(i);int inted = binVal / maxVal *high;cv::line(histImg,cv::Point(i,histSize),cv::Point(i,histSize - inted),cv::Scalar::all(0));}return histImg;}

2、去掉直方图两端bin为0或者小于某一数量的bin并记录去掉后两端的灰度值(mini,maxi),然后利用下面公式对颜色查找表进行拉伸:

(i - mini) * 255 / (maxi - mini) + 0.5
cv::Mat ImageHist::stretch(const cv::Mat &image,int minValue /* = 0 */){int mini = 0;for (;mini < histSize;++mini){if(hist.at<float>(mini) > minValue)break;}int maxi = histSize - 1;for (;maxi >= 0;--maxi){if(hist.at<float>(maxi) > minValue)break;}cv::Mat lookup(1,256,CV_8U);for (int i = 0;i < histSize;++i){if(i < mini)lookup.at<uchar>(i) = 0;else if(i > maxi)lookup.at<uchar>(i) = 255;elselookup.at<uchar>(i) =static_cast<uchar>((i - mini) * 255 / (maxi - mini) + 0.5);}cv::Mat result;cv::LUT(image,lookup,result);return result;}

结果:
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