Just Sort It（快速排序）

Judge Info

• Memory Limit: 1124KB
• Case Time Limit: 10000MS
• Time Limit: 10000MS
• Judger: Number Only Judger

Description

Sorting is one of the most important algorithm in computer sciences. Please learn it well.

本题需要的排序算法复杂度应该为nlogn，冒泡、选择的负责度为n^2，快排、归并、堆排序的复杂度为nlogn

本题的内存限制也是比较严格，所以建议大家使用堆排序，或者快速排序

Input

The first line of input contains , the number of test cases. There is only line for each test case. The first numberof each test case will indicates how many integer numbers are there for sort from smaller to larger. All numbers are in the range of .

Output

Output one line for every test case. The result of those integer numbers after sorting.

Sample Input

33 3 2 12 3 23 5 4 3

Sample Output

1 2 32 33 4 5

标准快排

#include<stdio.h>void quicksort(int *s, int l, int r){    if (l < r)    {        int i = l, j = r, x = s[l];        while (i < j)        {            while(i < j && s[j] >= x) j--;              if(i < j) s[i++] = s[j];            while(i < j && s[i] < x) i++;              if(i < j) s[j--] = s[i];        }        s[i] = x;        quicksort(s, l, i - 1);         quicksort(s, i + 1, r);    }}int main(){int t;scanf("%d",&t);while(t--){int n;int a[250000];scanf("%d",&n);for(int i=0;i<n;i++)scanf("%d",&a[i]);quicksort(a,0,n-1);for(int i=0;i<n;i++){printf("%d",a[i]);if(i<n-1)putchar(' ');}putchar('\n');}return 0;}