2054A==B?hdu

自己做这道题第一次用到了strchr这个函数；

strchr函数原型：extern char *strchr(const char *s,char c);查找字符串s中首次出现字符c的位置。

A == B ?

Time Limit: 1000/1000 MS (Java/Others)    Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 61130    Accepted Submission(s): 9517

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

 

Input

each test case contains two numbers A and B.

 

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

 

Sample Input

1 2
2 2
3 3
4 3

 

Sample Output

NO
YES
YES
NO

AC代码：

#include<stdio.h>
#include<string.h>
#define M 1000000
char s[M];
char p[M];
int fun(char *p)
{
    int n,i,j;
    n=strlen(p);
    if(strchr(p,'.')!=NULL)
    {
    for(i=n-1;p[i]=='0';i--);
    if(p[i]=='.')
    p[i]='\0';
    else
    p[i+1]='\0';
    }
    for(i=0;p[i]=='0'&&p[i+1]!='\0';i++);
    return i;
}
int main()
{
    while(~scanf("%s %s",s,p))
    {
                     int m,k,t;
                     int i,j;
                     for(i=fun(s),j=fun(p);s[i]!='\0'&&p[j]!='\0';i++,j++)
                     {
                                                             if(s[i]!=p[j])
                                                             {
                                                                           //printf("NO\n");
                                                                           break;
                                                             }
                     }
                     if(s[i]=='\0'&&p[j]=='\0')
                     printf("YES\n");
                     else
                     printf("NO\n");
                    
    }
    return 0;
}