杭电 1076（水题 暴力）

An Easy Task

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)

Total Submission(s): 14543    Accepted Submission(s): 9295

Problem Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

 

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.
Each test case contains two positive integers Y and N(1<=N<=10000).

 

Output

For each test case, you should output the Nth leap year from year Y.

 

Sample Input

32005 251855 122004 10000

 

Sample Output

2108190443236
Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.
 

 

Author

Ignatius.L

代码如下：

#include<stdio.h>int main(){    int n,y,t,i,j;    scanf("%d",&t);    while(t--)    {        scanf("%d%d",&y,&n);        for(i=0;i<n;i++)        {            for(j=y;;j++)            {                if(j%400==0||j%4==0&&j%100!=0)                {                    y=++j;                    break;                }            }        }        printf("%d\n",y-1);    }    return 0;}