dfs_poj_2531

题目链接：http://poj.org/problem?id=2531

Network Saboteur

Time Limit: 2000MS Memory Limit: 65536KTotal Submissions: 9246 Accepted: 4345

Description

A university network is composed of N computers. System administrators gathered information on the traffic between nodes, and carefully divided the network into two subnetworks in order to minimize traffic between parts. 
A disgruntled computer science student Vasya, after being expelled from the university, decided to have his revenge. He hacked into the university network and decided to reassign computers to maximize the traffic between two subnetworks. 
Unfortunately, he found that calculating such worst subdivision is one of those problems he, being a student, failed to solve. So he asks you, a more successful CS student, to help him. 
The traffic data are given in the form of matrix C, where Cij is the amount of data sent between ith and jth nodes (Cij = Cji, Cii = 0). The goal is to divide the network nodes into the two disjointed subsets A and B so as to maximize the sum ∑Cij (i∈A,j∈B).

Input

The first line of input contains a number of nodes N (2 <= N <= 20). The following N lines, containing N space-separated integers each, represent the traffic matrix C (0 <= Cij <= 10000). 
Output file must contain a single integer -- the maximum traffic between the subnetworks. 

Output

Output must contain a single integer -- the maximum traffic between the subnetworks.

Sample Input

30 50 3050 0 4030 40 0

Sample Output

90

基础的搜索题，用搜索穷举出各种状态，取最大值即可，搜索时基础，不难，计算最大值的时候，脑子抽了， 居然错了好几次

代码：

#include <stdio.h>#include <string.h>int map[22][22], n, Max;short mark[22]; ///标记数组void visit(int pos, int sum){    int i;    for( i = 1; i <= n; i++)    {        if(mark[i]){ sum -= map[pos][i]; }  ///删除重复部分        else { sum += map[pos][i]; }     ///添加    }    if(Max < sum)Max = sum;       for( i = pos + 1; i <= n; i++)    {        mark[i] = 1;        visit(i, sum);        mark[i] = 0;    }}int main(){    int i, j;    while(~scanf("%d",&n))    {        Max = 0;        memset(map,0,sizeof(map));        memset(mark,0,sizeof(mark));        for( i = 1; i <= n; i++)        {            for( j = 1; j <= n; j++)            {                scanf("%d",&map[i][j]);            }        }        for( i = 1; i <= n; i++)        {            mark[i] = 1;            visit(i, 0);  ///dfs 函数  写visit 写习惯了            mark[i] = 0;        }        printf("%d\n",Max);    }    return 0;}

运行结果：