zoj 1414 Number Steps

//坐标上有数字条件x>y,x-y==0||x-y==2,奇数x+y-1，偶数x+y

#include<stdio.h>int main(){ int n,x,y;scanf("%d",&n);while(n--){scanf("%d%d",&x,&y);if(x<y||x-y>2||x-y==1) printf("No Number\n");else{if(x % 2)if(x + y -1<5000) printf("%d\n",x+y-1);else printf("No Number\n");else {if(x + y<=5000) printf("%d\n",x+y);else printf("No Number\n");}}}return 0;}