Leetcode Best Time to Buy and Sell Stock II

这道题由于可以不断地买卖，所以只要当前股票价格比前一次高了就可以加到profit里面去。

#include <iostream>#include <vector>using namespace std;class Solution {public:int maxProfit(vector<int> &prices) {if (prices.size() == 0){return 0;}int profit = 0;for (int i = 1; i < prices.size(); ++i){if (prices[i] > prices[i - 1]){profit += prices[i] - prices[i - 1];}}return profit;}};int main(){std::vector<int> prices;prices.push_back(1);prices.push_back(2);Solution s;cout<<s.maxProfit(prices)<<endl;return 0;}