poj 2498 StuPId
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之前做过一道类似的题目,有一道。。。这题其实还好,不是那么阴。。。
至少题目里面有打(!)提醒。。。
#include <stdio.h>#include <string.h>char Num[10];int factors[]={9,3,7};void process(){int missPos; //保存丢失了哪一位int i;int sum=0;int numInt;for(i=strlen(Num)-1;i>=0;i--){if(Num[i]=='?')missPos=i;else{numInt=Num[i]-48;sum+=numInt*(factors[(strlen(Num)-1-i)%3]);}}//printf("sum == %d\n",sum);for(i=0;i<10;i++)if((sum+i*(factors[(strlen(Num)-1-missPos)%3]))%10==0){Num[missPos]=i+48;break;}//sum+=i*(factors[(strlen(Num)-1-missPos)%3]);//printf("sum == %d\n",sum);printf("%s\n\n",Num);}int main(){int n;scanf("%d",&n);int count=n;int i;while(count--){scanf("%s",Num);printf("Scenario #%d:\n",n-count);process();}return 0;}
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