poj 2538 WERTYU

来源：互联网发布：日本女演员知乎编辑：程序博客网时间：2024/06/05 00:09

简单暴力的一道题，以前做过，现在就不浪费时间自己打表了。。。

粘上一种稍微聪明的方法和一种最笨的方法。。。

聪明一些的方法：

#include <cstdio>#include <cstring>const char dic[]="  1234567890-=QWERTYUIOP[]\\ASDFGHJKL;'ZXCVBNM,./";char str[1000];int main(){int i,j,l,l2=strlen(dic);while (gets(str)!=NULL){l=strlen(str);for (i=0;i<l;i++){for (j=1;str[i]!=dic[j] && j<l2;j++);if (j<l2)printf("%c",dic[j-1]);elseprintf(" ");}printf("\n");}}

最笨的方法：

#include"stdio.h"#include"string.h"int main(){char s[100];char a[100]; s[';'] = 'L';s['L'] = 'K';s['K'] = 'J';s['J'] = 'H';s['H'] = 'G';s['G'] = 'F';s['F'] = 'D';s['D'] = 'S';s['S'] = 'A';s[','] = 'M';s['M'] = 'N';s['N'] = 'B';s['B'] = 'V';s['V'] = 'C';s['C'] = 'X';s['X'] = 'Z';s['['] = 'P';s['P'] = 'O';s['O'] = 'I';s['I'] = 'U';s['U'] = 'Y';s['Y'] = 'T';s['T'] = 'R';s['R'] = 'E';s['E'] = 'W';s['W'] = 'Q';s['/'] = '.';s['\''] = ';';s[']'] = '[';s['\\'] = ']';s['.'] = ',';s['='] = '-';s['-'] = '0';s['0'] = '9';s['9'] = '8';s['8'] = '7';s['7'] = '6';s['6'] = '5';s['5'] = '4';s['4'] = '3';s['3'] = '2';s['2'] = '1';s['1'] = '`';s[' ']=' ';while(gets(a)){int i;for(i=0;i<strlen(a);i++)printf("%c",s[a[i]]);printf("\n");}return 0;}

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