【LeetCode】Pascal's Triangle II
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Given an index k, return the kth row of the Pascal's triangle.
For example, given k = 3,
Return [1,3,3,1]
.
Note:
Could you optimize your algorithm to use only O(k) extra space?
class Solution {public: vector<int> getRow(int rowIndex){ vector<int> ret; int i = 0; long long num = 1; int n = rowIndex; for(;i<=rowIndex;){ ret.push_back(num); i++; num = num*n/i; n--; } return ret; }};
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