2503 Babelfish 二分 字典树 map容器

Description

You have just moved from Waterloo to a big city. The people here speak an incomprehensible dialect of a foreign language. Fortunately, you have a dictionary to help you understand them.

Input

Input consists of up to 100,000 dictionary entries, followed by a blank line, followed by a message of up to 100,000 words. Each dictionary entry is a line containing an English word, followed by a space and a foreign language word. No foreign word appears more than once in the dictionary. The message is a sequence of words in the foreign language, one word on each line. Each word in the input is a sequence of at most 10 lowercase letters.

Output

Output is the message translated to English, one word per line. Foreign words not in the dictionary should be translated as "eh".

Sample Input

dog ogdaycat atcaypig igpayfroot ootfrayloops oopslayatcayittenkayoopslay

Sample Output

catehloops

》》》》》》》》二分法》》》》》》》》》》》》》》

#include <algorithm>#include <cstdlib>#include <cstring>#include <cstdio>using namespace std;struct node{char compare[11];char out[11];}s[110000];int cmp( const void *a, const void *b ){node *x=( node *)a;node *y=( node *)b;return strcmp( x->compare, y->compare );}void search( char *str, int n ){int low=0, high=n, mid, flag;flag=0;while( low<=high ){mid=( low+high )/2;if( strcmp( str, s[mid].compare )==0 ){flag=1;printf( "%s\n",s[mid].out );break;}else if( strcmp( str, s[mid].compare )>0 )low=mid+1;else high=mid-1;}if( flag==0 )printf( "eh\n" );}int main(){char str[110];char a[110],b[110];int n=0;while( gets( str ),str[0] ){sscanf( str,"%s%s",a,b );strcpy( s[n].out, a );strcpy( s[n].compare, b );n++;}qsort( s, n, sizeof( s[0] ), cmp );while( gets( str ) ){search( str, n-1 );}return 0;}

《《《《《《《《《《《字典树》》》》》》》》》》》》》》》》

#include <algorithm>#include <cstring>#include <cstdio>using namespace std;struct node{struct node *son[30];char str[110];};node *root, *now, *next;void build( char *str, char *st ){int i, j;int len=strlen( str );now=root;for( i=0;i<len;i++ ){if( now->son[str[i]-'a']==0 ){next=( struct node * )malloc( sizeof( struct node ) );now->son[str[i]-'a']=next;now=next;for( j=0;j<26;j++ )next->son[j]=0;}else{now=now->son[str[i]-'a'];}}strcpy( now->str, st );}void search( char *str ){int i, len;len=strlen( str );now=root;for( i=0;i<len;i++ ){if( now->son[str[i]-'a']==0 ){printf( "eh\n" );return ;}now=now->son[str[i]-'a'];}printf( "%s\n", now->str );}int main(){int i, j, k, t;char str[110];char a[110],b[110];root=( struct node * )malloc( sizeof( struct node ) );for( i=0;i<26;i++ ) root->son[i]=0;while( gets( str ),str[0] ){sscanf( str,"%s%s",a,b );build( b, a );}while( gets( str ) ){search( str );}return 0;}
《《《《map容器《《《《
#include <algorithm>#include <iostream>#include <cstring>#include <cstdio>#include <string>#include <map>using namespace std;int main(){    char str[101];    char a[101], b[101];    map<string,string>q;    while( gets( str ),str[0] )    {        sscanf( str, "%s%s", a, b );        q[b]=a;    }    while( gets( str ) )    {        q.count( str )?cout<<q[str]<<endl:cout<<"eh"<<endl;    }    return 0;}