应用（*p）[n]指针数组

#include <stdio.h>

#include <stdlib.h>

void main()

{

float score[][4] ={{60,70,80,90},{56,89,67,88},{34,78,90,66}};

float *search(float(*pointer)[4]);

float *p;

int i;

for(i = 0;i<3;i++)

{

p = search(score+i);

if(p==*(score+i))

{

printf("No.%d scores:",i);

int j;

for(j = 0;j<4;j++)

{

printf("\t%5.2f",*(p+j));

}printf("\n");

}

}

}

float *search(float(*pointer)[4])

{

int i;

float *p;

p = *(pointer+1);//+1为了区别不及格是找到的pointer（指向一个4维数组）

for(i = 0;i<4;i++)

{

if(*(*pointer+i)<60) p = *pointer;

}

return p;

}