1065. A+B and C (64bit) (20)

Given three integers A, B and C in [-2⁶³, 2⁶³], you are supposed to tell whether A+B > C.

Input Specification:

The first line of the input gives the positive number of test cases, T (<=10). Then T test cases follow, each consists of a single line containing three integers A, B and C, separated by single spaces.

Output Specification:

For each test case, output in one line "Case #X: true" if A+B>C, or "Case #X: false" otherwise, where X is the case number (starting from 1).

Sample Input:

31 2 32 3 49223372036854775807 -9223372036854775808 0

Sample Output:

Case #1: falseCase #2: trueCase #3: false

分析：

（1）溢出的情况特殊处理。

（2）思路太复杂的估计就不对或者麻烦了。

#include<string>#include<cstdio>#include<iostream>using namespace std;int main (){int t,i;cin>>t;for (i=1;i<=t;i++){long long int a,b,c;scanf("%lld%lld%lld",&a,&b,&c);long long int d=a+b;   // why ?  a+b is not ok ?if (a>0&&b>0&&d<=0) {printf ("Case #%d: true\n",i);}else if (a<0&&b<0&&d>=0) {printf("Case #%d: false\n",i);}else{if (a+b>c) printf("Case #%d: true\n",i);else printf("Case #%d: false\n",i);}//cout<<a<<" "<<b<<" "<<a+b<<" "<<d<<endl;}return 0;}