给一个开始时间和一个结束时间，求中间的连续时间（用java实现）？

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给一个开始时间和一个结束时间，求中间的连续时间（用java实现）？如：开始时间为140825，结束时间为140902，那连续时间为 140825，140826，140827，140828，140829，140830，140831，140901，140902

 import java.text.ParseException;import java.text.SimpleDateFormat;import java.util.ArrayList;import java.util.Calendar;import java.util.Date;import java.util.GregorianCalendar;import java.util.List;/** *时间格式化工具类 */public class ChartDateFormatUtils {/** * 获取两个时间相差的天数 *  * @param date1 * @param date2 * @return */public static int getBetweenDays(Date date1, Date date2) {Calendar cal = Calendar.getInstance();cal.setTime(date1);long time1 = cal.getTimeInMillis();cal.setTime(date2);long time2 = cal.getTimeInMillis();long between_days = (time2 - time1) / (1000 * 3600 * 24);return Integer.parseInt(String.valueOf(between_days));}/** * 获取连续时间 *  * @param tempList * @return * @throws ParseException */@SuppressWarnings("deprecation")public static List<String> getContinuousTime(List<String> tempList) throws ParseException {String startTime = tempList.get(0);String endTime = tempList.get(tempList.size() - 1);SimpleDateFormat sdf = new SimpleDateFormat("yyMMdd");Date startDate = sdf.parse(startTime);Date endDate = sdf.parse(endTime);int betweenDay = getBetweenDays(startDate, endDate) + 1;Calendar curTime = new GregorianCalendar(startDate.getYear(), startDate.getMonth(), startDate.getDate());SimpleDateFormat dateformat2 = new SimpleDateFormat("yyMMdd");List<String> dataList = new ArrayList<String>();for (int i = 1; i <= betweenDay; i++) {String dateKey = dateformat2.format(curTime.getTime());dataList.add(dateKey);curTime.add(Calendar.DATE, 1);}return dataList;}public static void main(String[] args) {List<String> tempList = new ArrayList<String>();tempList.add("140715");tempList.add("140717");tempList.add("140817");try {for (String str : getContinuousTime(tempList)) {System.out.println(str);}} catch (ParseException e) {e.printStackTrace();}}}

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