UVa 10491 - Cows and Cars
来源:互联网 发布:c语言 bmp 像素值读取 编辑:程序博客网 时间:2024/04/27 22:48
題目:有m+n個們,每個門後面有牛或者車;有n只牛,m輛車,你選擇其中1個;
然後打開其中的k你沒有選中的門後是牛的,問你改變選時得到車的概率。
說明:數學題,概率。全概率公式即可:
說明:第1001了O(∩_∩)O~
#include <stdio.h> int main(){int cow,car,show;while (~scanf("%d%d%d",&cow,&car,&show)) printf("%.5lf\n",(cow+car-1.0)*car/(cow+car)/(cow+car-show-1.0));return 0;}
0 0
- UVA 10491-Cows and Cars
- UVA - 10491 Cows and Cars
- UVa 10491 - Cows and Cars
- UVA - 10491 Cows and Cars
- UVa 10491 - Cows and Cars
- UVA 10491 Cows and Cars
- uva 10491 Cows and Cars
- UVa 10491 Cows and Cars
- UVA 10491 Cows and Cars
- uva 10491 uva 10491 Cows and Cars
- Cows and Cars UVA
- Cows and Cars UVA
- uva 10491 - Cows and Cars(概率)
- UVa 10491 - Cows and Cars 概率
- UVA 10491 Cows and Cars 概率
- UVA - 10491 Cows and Cars 概率
- UVA 10491 Cows and Cars(概率)
- UVa 10491 - Cows and Cars(概率)
- 数据库关系图
- COM,OLE,ActiveX
- Spring缓存机制的理解
- 排序题目一网打尽
- 详细解析Java中抽象类和接口的区别【大赞】
- UVa 10491 - Cows and Cars
- 新技能get,山寨版批量kill mysql连接
- IT忍者神龟之端口查杀
- 汉澳sinox通过ndis运行windows驱动程序
- 机器学习经典书籍小结
- 地铁换乘
- sql 删除重复列代码
- 参数记录
- [LeetCode] Longest Common Prefix