[leetcode] Simplify Path
来源:互联网 发布:淘宝女装宝贝描述 编辑:程序博客网 时间:2024/06/18 09:21
Given an absolute path for a file (Unix-style), simplify it.
For example,
path = "/home/"
, => "/home"
path = "/a/./b/../../c/"
, => "/c"
Corner Cases:
参考链接:http://blog.csdn.net/maverick1990/article/details/23275051- Did you consider the case where path =
"/../"
?
In this case, you should return"/"
. - Another corner case is the path might contain multiple slashes
'/'
together, such as"/home//foo/"
.
In this case, you should ignore redundant slashes and return"/home/foo"
.
思路:
简化一个Unix文件路径,注意:
(1)"/." 表示本级目录,可直接忽略
(2)"/.." 表示返回上一级目录,即若上一级目录存在,连同"/.."一并删除,否则只删除/..
(3)若去除冗余后路径为空,返回"/"
(4)若包含连续"/",删除多余的
(5)若路径不是单个“/”,删除路径最后一个“/”
分析:一开始用逐个字符判断的方法,考虑很多边界条件。后来用字符串分割的思想,比较简明。思路如下:
(1)用“/”分割字符串,遍历每个分割部分,存入一个vector<string>中
(2)若当前分割部分为空,证明有连续的"/"或是最后一个“/”,忽略
(3)若当前部分为“.”,忽略
(4)若当前部分为“..”,若vector不为空,去除vector最后一个元素
(5)再将vector中的string用“/”连起来,得到结果
代码:
class Solution {public: string simplifyPath(string path) { string ans,now; vector<string> list; stringstream ss(path); while(getline(ss,now,'/')){ if(now.size()==0 || now==".") continue; if(now==".."){ if(!list.empty()) list.pop_back(); } else{ list.push_back(now); } } for(int i=0;i<list.size();i++){ ans+="/"; ans+=list[i]; } if(ans.size()==0) ans="/"; return ans; }};
0 0
- LeetCode: Simplify Path
- LeetCode Simplify Path
- LeetCode : Simplify Path
- [Leetcode] Simplify Path
- [leetcode] simplify path
- [LeetCode] Simplify Path
- leetcode 100: Simplify Path
- [leetcode]Simplify Path
- [LeetCode]Simplify Path
- [leetCode] Simplify Path
- [leetcode]Simplify Path
- [leetcode] Simplify Path
- [LeetCode] Simplify Path
- leetcode simplify path
- Leetcode: Simplify Path
- LeetCode题解:Simplify Path
- [LeetCode] Simplify Path
- LeetCode Simplify Path
- jquery判断checkbox是否被选中
- 八大排序算法_C++实现及对比
- i2c kobject
- JQuery中serialize()用法
- Lingpipe中的spell模块-拼写纠错
- [leetcode] Simplify Path
- 必须记住的756-33-44-66
- Json转换利器Gson之实例一-简单对象转化和带泛型的List转化
- ASM CRS 实例启动和关闭
- ZOJ 3810 A Volcanic Island
- 报ORA-4031错误时,我们通常可以根据Oracle无法分配多少字节的内存,来判断共享池碎片的严重程度,以下是4031错误官方的解释
- 阿拉伯数字转换为大写金额
- 11gR2启动ASM实例时遭遇ORA-29701
- ASP.NET开发,简化与封装