Search Insert Position

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Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4

[1,3,5,6], 0 → 0

思路:典型排序搜索。

class Solution {public:    int searchInsert(int A[], int n, int target) {        if (A == NULL) {            return NULL;        }                int start = 0;        int end = n - 1;        int mid;                while (start <= end)        {            mid = start + (end - start) / 2;            if  (A[mid] > target) {               end = mid - 1;            }            else if (A[mid] < target) {                start = mid + 1;            }            else if (A[mid] == target) {                return mid;            }        }            return target>=A[mid] ? mid+1:mid;    }};


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