编程之美：电话号码对应英文单词（ 程序实现）

/************************************************************************//* 实现：将输入的手机号码对应手机键盘的字母形成组合，并打印输出 输入： 电话号码位数，对应的电话号码 输出：电话号码对应所用字母组合*//************************************************************************/#include <cstdio>#include <assert.h>#include <cstring>using namespace std;char dict[10][5]={    "",//0    "",//1    "ABC",//2    "DEF",//3    "GHI",//4    "JKL",//5    "MNO",//6    "PQRS",//7    "TUV",//8    "WXYZ"//9};int total[10]={0,0,3,3,3,3,3,4,3,4};void printAllStr(int * arr,int len);int main(int argc,char * argv[]){  int telNum = 0; while(scanf("%d",&telNum)!=EOF) {     int* arr = new int[telNum];     if(!arr)     {printf("failed to create new arr\n");break;     }     for(int i=0;i<telNum;++i)     {    scanf("%d",arr+i);     }     // TODO print function     printAllStr(arr,telNum);     delete []arr; } return 0;}void printAllStr(int * arr, int len){    int* res = new int[len];    assert(res);       memset(res,0,sizeof(int)*len);        int resMulty = 1;    for(int i = 0; i< len ; ++i)    {if(total[arr[i]])       resMulty *= total[arr[i]];    }        printf("\n resMulty=%d\n",resMulty);        int changeI = 0;    int  ordinary = 1;    while(true)    {printf("[%03d]:",ordinary);for(int i =0;i<len;++i)    printf("%c",dict[ arr[i] ][  res[i] ]);puts("");ordinary ++;changeI = 0;while(changeI<len){      // 前一组的序号满了，则：先改变下标，再改变对应下标的输出序号      if(res[ changeI  ]<total[ arr[changeI ] ]-1)     {res[ changeI ]++;break;     }     else     {    res[ changeI ] = 0;    changeI++;     }        } if(changeI == len)    break;    }    delete []res;       puts("\nend of one case");}