编程算法 - 连续和最大的子数组 代码(C)

连续和最大的子数组 代码(C)

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题目: 在一个数组中, 找出连续和最大的子序列.

使用两个变量, 一个变量存储当前值, 一个变量存储最大值, 并设一个临时数组, 用于更新最大和数组.

时间复杂度O(n).

代码:

/* * main.cpp * *  Created on: 2014.9.19 *      Author: spike */#include <iostream>#include <vector>#include <climits>using namespace std;int FindSequence (int data[], int length, vector<int>& vi){if (data == NULL || length <= 0)return INT_MIN;int greatest = INT_MIN;int cur = 0;vector<int> tmp;for (int i=0; i<length; ++i) {if (cur <= 0) {cur = data[i];tmp.clear();tmp.push_back(data[i]);} else {cur += data[i];tmp.push_back(data[i]);}if (cur > greatest) {vi = tmp;greatest = cur;}}return greatest;}int main(void){int data[] = {1, -2, 3, 10, -4, 7, 2, -5};int length = sizeof(data)/sizeof(data[0]);vector<int> vi;int g = FindSequence(data, length, vi);cout << g << ": ";for (size_t i=0; i<vi.size(); ++i) {cout << vi[i] << " ";}cout << endl;    return 0;}

输出:

18: 3 10 -4 7 2