uva 10131 Is Bigger Smarter?
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近几天刚开始接触dp。
队友推荐的第一道题(最长上升子序列) 就是要严格按照递增顺序走的 。
先排好序,然后就跟矩阵嵌套一样。
其实有个二分的,只不过貌似不能用在这道题上,因为要输出路径的。
代码如下:
#include<stdio.h>#include<string.h>#include<algorithm>using namespace std;const int M=1002;struct node{ int wei; int iq; int id;} p[M];int path[M];int dp[M];int MAX=-1;int k=-1;int cmp(node a,node b){ if(a.wei!=b.wei) return a.wei<b.wei; if(a.iq!=b.iq) return a.iq>b.iq;}int n;//int lis()//{// b[0]=p[0].id;// int cur=1;// for(int i=0; i<n; i++)// {// int j=lower_bound(b,b+cur,p[i].id)-b;// b[j]=p[i].id;// if(j>=cur)// cur++;// }// return cur;//}void print(int i){ if(MAX--) { print(path[i]); printf("%d\n",p[i].id); }}int main(){ //freopen("in.txt","r",stdin); n=0; while(~scanf("%d%d",&p[n].wei,&p[n].iq)) { p[n++].id=n; } sort(p+1,p+n+1,cmp); for(int i=1;i<n;i++) { path[i]=1; dp[i]=1; } for(int i=1; i<n; i++) for(int j=1; j<i; j++) { if(p[i].wei>p[j].wei&&p[i].iq<p[j].iq&&dp[i]<dp[j]+1) { dp[i]=dp[j]+1; path[i]=j; } if(dp[i]>MAX) MAX=dp[i],k=i; } printf("%d\n",MAX); print(k); return 0;}
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