Search Insert Position

Given a sorted array and a target value, return the index if the target is found. If not, return the index where it would be if it were inserted in order.

You may assume no duplicates in the array.

Here are few examples.
[1,3,5,6], 5 → 2
[1,3,5,6], 2 → 1
[1,3,5,6], 7 → 4
[1,3,5,6], 0 → 0

答案

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1. public class Solution { 
2.     public int searchInsert(int[] A,int target) { 
3.         if(target<=A[0]) 
4.         { 
5.             return 0; 
6.         } 
7.         if(target>A[A.length-1]) 
8.         { 
9.             return A.length; 
10.         } 
11.         int start=0; 
12.         int end=A.length-1; 
13.         while(start<=end) 
14.         { 
15.             int middle=start+(end-start)/2; 
16.             if(A[middle]==target) 
17.             { 
18.                 return middle; 
19.             } 
20.             else 
21.             { 
22.                 if(target>A[middle]) 
23.                 { 
24.                     if(target<=A[middle+1]) 
25.                     { 
26.                         return middle+1; 
27.                     } 
28.                     start=middle+1; 
29.                 } 
30.                 else 
31.                 { 
32.                     if(target>A[middle-1]) 
33.                     { 
34.                         return middle; 
35.                     } 
36.                     end=middle-1; 
37.                 } 
38.                  
39.             } 
40.         } 
41.         return 0; 
42.     } 
43. } 

public class Solution {    public int searchInsert(int[] A, int target) {        if(target<=A[0])        {            return 0;        }        if(target>A[A.length-1])        {            return A.length;        }        int start=0;        int end=A.length-1;        while(start<=end)        {            int middle=start+(end-start)/2;            if(A[middle]==target)            {                return middle;            }            else            {                if(target>A[middle])                {                    if(target<=A[middle+1])                    {                        return middle+1;                    }                    start=middle+1;                }                else                {                    if(target>A[middle-1])                    {                        return middle;                    }                    end=middle-1;                }                            }        }        return 0;    }}