UI线程阻塞问题

来源：互联网发布：sql select两个表编辑：程序博客网时间：2024/05/22 09:40

两种方法：

1.view.post；

2.AsyncTask；

（1）java文件：
import android.app.Activity;
import android.graphics.Bitmap;
import android.os.AsyncTask;
import android.os.Bundle;
import android.view.Menu;
import android.view.MenuItem;
import android.view.View;
import android.view.animation.TranslateAnimation;
import android.widget.Button;
import android.widget.TextView;

public class MyActivity extends Activity {

    private Button button2=null;

    protected void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_my);

        Button button1=(Button) findViewById(R.id.button1);

        TranslateAnimation animation=new TranslateAnimation(0,150,0,0);
        animation.setRepeatCount(100);
        animation.setDuration(2000);
        button1.setAnimation(animation);

        final Button button2=(Button)findViewById(R.id.button2);

        button2.setOnClickListener(new View.OnClickListener() {
            @Override
            public void onClick(View view) {
                new Thread2().execute();
            }

            /*方法一：v.post     可读性差，不易维护
            public void onClick(final View v) {
                new Thread(new Runnable() {
                    public void run() {
                        try {
                            Thread.sleep(3000);
                        } catch (InterruptedException e) {
                            e.printStackTrace();
                        }
                        v.post(new Runnable() {
                            @Override
                            public void run() {
                                TextView view=(TextView) v;
                                view.setText(""+10);
                            }
                        });
                    }
                    }).start();
                }*/

            //方法二:AsyncTask方法
            class Thread2 extends AsyncTask<String, Integer, Integer> {
                protected void onPostExecute(Integer sum) {
                           button2.setText(""+10);
                }
                protected Integer doInBackground(String... url) {
                    try {
                        Thread.sleep(3000);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    int sum =10;
                    return sum;
                }
            }
        });
        }
    }

（2）xml文件：

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