大数加法的字符串实现

来源：互联网发布：linux下安装chrome 编辑：程序博客网时间：2024/05/16 16:20

#include<iostream>#include <string.h>#include <stdio.h>using namespace std;char s1[200],s2[200],sum[210];void add(){    int lena=strlen(s1);    int lenb=strlen(s2);    int maxlen=(lena<lenb)?lenb:lena;    int carry=0,k=0;    while(lena-->0 && lenb-->0)    {        int left=s1[lena]-'0';        int right=s2[lenb]-'0';        int s=left+right+carry;        carry=s/10;        s%=10;        sum[k++]=s+'0';    }    if(lena<=0)    {        while(lenb-->0)        {            int left=0;            int right=s2[lenb]-'0';            int s=left+right+carry;            carry=s/10;            s%=10;            sum[k++]=s+'0';        }    }    else if(lenb<=0)    {        while(lena-->0)        {            int left=s1[lena]-'0';            int right=0;            int s=left+right+carry;            carry=s/10;            s%=10;            sum[k++]=s+'0';        }    }    if(carry!=0)        sum[k++]=carry+'0';    sum[k]='\0';    strrev(sum);}int main(){    cin>>s1>>s2;    add();    cout<<"result is "<<sum<<endl;    return 0;}

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