Leetcode_find-minimum-in-rotated-array(c++ version)
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题目 https://oj.leetcode.com/problems/find-minimum-in-rotated-sorted-array/
Suppose a sorted array is rotated at some pivot unknown to you beforehand.
(i.e., 0 1 2 4 5 6 7
might become 4 5 6 7 0 1 2
).
Find the minimum element.
You may assume no duplicate exists in the array.
思路:二分的找,一半是有序的,一半可能是有序的,可能是乱序的,也就是这个问题的子问题。
即这个问题是a,a = b + a/2, b是一个有序的序列,取b第一个元素 和 a/2 最小的元素 的较小值即可。
代码:
class Solution {public: int findMin(vector<int> &num) { if(num.size()==1) return num[0]; else if(num.size()==2) return min(num[0], num[1]); int mid = num.size() / 2; if(num[0] < num[mid]) { vector<int> subvec(num.begin()+mid+1, num.end()); return min(findMin(subvec), num[0]); } else { vector<int> subvec(num.begin(), num.begin()+mid+1); return min(num[mid+1], findMin(subvec)); } }};
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