单用户登陆,踢出前一个同名用户

来源：互联网发布：江湖家居源码编辑：程序博客网时间：2024/06/09 10:11

*******在web.xm中做session过期时间设置************
<session-config>
<session-timeout>15</session-timeout>
</session-config>

******************LogonAction.java******************************
ActionServlet servlet = this.getServlet();
HttpSession session = request.getSession();
ServletContext servletContext = servlet.getServletContext();
HttpSession oldSession = (HttpSession) servletContext.getAttribute(loginId);
boolean isFirstLogin = (oldSession == null);
boolean isSameLogin = (oldSession != null) && oldSession.getId().equals(session.getId());
if (isFirstLogin || !isSameLogin) {
             servletContext.setAttribute(loginId, session);
}

******************在其他需要验证的action中加入一下代码*****************
ActionServlet servlet = this.getServlet();
ServletContext servletContext = servlet.getServletContext();
HttpSession oldSession = (HttpSession) servletContext.getAttribute(loginId);
if(session.getAttribute(Constants.CURRENT_USER)==null){
   session.setAttribute("message", "timeout");
   return mapping.findForward("timeoutfail");
}
if (oldSession != null&&!(oldSession.getId().equals(session.getId())))  {
      request.getSession().invalidate();
      return (mapping.findForward("failoldsession"));
}