Hat's Fibonacci(杭电1250）

Hat's Fibonacci

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 7854    Accepted Submission(s): 2551

Problem Description

A Fibonacci sequence is calculated by adding the previous two members the sequence, with the first two members being both 1.
F(1) = 1, F(2) = 1, F(3) = 1,F(4) = 1, F(n>4) = F(n - 1) + F(n-2) + F(n-3) + F(n-4)
Your task is to take a number as input, and print that Fibonacci number.

 

Input

Each line will contain an integers. Process to end of file.

 

Output

For each case, output the result in a line.

 

Sample Input

100

 

Sample Output

4203968145672990846840663646
#include<stdio.h>#include<string.h>#define N 10000    //N很关键，N=10000或者20000都可以AC，N取得过小会错。 int str[N][260];int main(){    memset(str,0,sizeof(str));    str[1][0]=1;    str[2][0]=1;    str[3][0]=1;    str[4][0]=1;    int i,j,ans=0,c,n;    for(i=5;i<N;i++)    {        for(j=0,c=0;j<260;j++)        {            ans=str[i-1][j]+str[i-2][j]+str[i-3][j]+str[i-4][j]+c;            c=ans/100000000;            str[i][j]=ans%100000000;   //每一个数组存8位数字，c来控制是否进位。         }    }    while(scanf("%d",&n)!=EOF)    {        j=259;        while(!str[n][j])    //将首0清除。         j--;        printf("%d",str[n][j]);        for(i=j-1;i>=0;i--)        printf("%08d",str[n][i]);//每8位输出，不足8位自动补0；         printf("\n");    }    return 0;}