判断是不是中文,判断手机号码,计算字符串长度

来源：互联网发布：网上买门用什么软件编辑：程序博客网时间：2024/06/07 15:47

// 正则判断手机号码地址格式- (BOOL)isMobileNumber:(NSString *)mobileNum{       /**        * 手机号码        * 移动：134[0-8],135,136,137,138,139,150,151,157,158,159,182,187,188        * 联通：130,131,132,152,155,156,185,186        * 电信：133,1349,153,180,189        */       NSString * MOBILE = @"^1(3[0-9]|5[0-35-9]|8[025-9])\\d{8}$";       /**        10         * 中国移动：China Mobile        11         * 134[0-8],135,136,137,138,139,150,151,157,158,159,182,187,188        12         */       NSString * CM = @"^1(34[0-8]|(3[5-9]|5[017-9]|8[278])\\d)\\d{7}$";       /**        15         * 中国联通：China Unicom        16         * 130,131,132,152,155,156,185,186        17         */       NSString * CU = @"^1(3[0-2]|5[256]|8[56])\\d{8}$";       /**        20         * 中国电信：China Telecom        21         * 133,1349,153,180,189        22         */       NSString * CT = @"^1((33|53|8[09])[0-9]|349)\\d{7}$";       /**        25         * 大陆地区固话及小灵通        26         * 区号：010,020,021,022,023,024,025,027,028,029        27         * 号码：七位或八位        28         */      // NSString * PHS = @"^0(10|2[0-5789]|\\d{3})\\d{7,8}$";         NSPredicate *regextestmobile = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", MOBILE];     NSPredicate *regextestcm = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CM];     NSPredicate *regextestcu = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CU];     NSPredicate *regextestct = [NSPredicate predicateWithFormat:@"SELF MATCHES %@", CT];        if (([regextestmobile evaluateWithObject:mobileNum] == YES)    || ([regextestcm evaluateWithObject:mobileNum] == YES)    || ([regextestct evaluateWithObject:mobileNum] == YES)    || ([regextestcu evaluateWithObject:mobileNum] == YES))    {        return YES;    }    else     {        return NO;    }}

主要是将oc字符串转成c的字符串(char*)，然后判断c的字符串的长度，因为中文字符占得长度是英文字符的两倍。//判断一个字符书不是中文。-(BOOL)isChinese:(NSString*)c{    int strlength = 0;    char* p = (char*)[ccStringUsingEncoding:NSUnicodeStringEncoding];    for (int i=0 ; i<[c lengthOfBytesUsingEncoding:NSUnicodeStringEncoding] ;i++) {        if (*p) {            p++;            strlength++;        }        else {            p++;        }    }    return ((strlength/2)==1)?YES:NO;}检验：    NSString* str  = @"我";    NSLog(@"%d",[selfisChinese:str]);    NSString* str2 = @"w";    NSLog(@"%d",[selfisChinese:str2]);//计算一段字符串的长度，两个英文字符占一个长度。- (int)countTheStrLength:(NSString*)strtemp {    int strlength = 0;    char* p = (char*)[strtempcStringUsingEncoding:NSUnicodeStringEncoding];    for (int i=0 ; i<[strtemp lengthOfBytesUsingEncoding:NSUnicodeStringEncoding] ;i++) {        if (*p) {            p++;            strlength++;        }        else {            p++;        }    }    return (strlength+1)/2;}

for(int i=0; i< [c length];i++){                int a = [c characterAtIndex:i];                if( a > 0x4e00 && a < 0x9fff)            return YES;            }    return NO;

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