用for和while循环求e的值[e=1+1/1!+1/2!+1/3!+1/4!+1/5!+...+1/n!]

/*编写程序，根据以下公式求e的值。要求用两种方法计算:1)for循环，计算前50项2)while循环，直至最后一项的值小于10-4e=1+1/1!+1/2!+1/3!+1/4!+1/5!+...+1/n!*/#include<stdio.h>//=====================================================//用for求e的值double For(){double sum=1,temp=1;int i;for(i=1;i<50;i++){temp/=i;sum+=temp;}return sum;}//=====================================================//用while循环求e的值double While(){double sum=1;//首项设置为1double temp = 1;int i=1;while(temp>=1e-4){//【e=1+1/1!+1/2!+1/3!+1/4!+1/5!+...+1/n!】temp = temp/i;//第二项1/1,即1/1!;第三项1/2,即1/2!;第四项(1/2)/3,即1/3!...sum = sum+temp;i++;}return sum;//返回sum}//主函数int main(){double a = For();double b = While();printf("用for循环求出e的前50项的和是%lf\n",a);printf("用while循环求出e和是%lf\n",b);return 0;}