Reverse Words in a String
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题目要求:
Given an input string, reverse the string word by word.
For example,
Given s = "the sky is blue
",
return "blue is sky the
".
分析:
初步分析,有两种思路:
1、采用剑指offer中所讲的两次翻转字符串解法,先将整个字符串翻转一次,再对每个单词翻转一次。
2、遍历字符串,将单词抠出来拼接成目标串dest,具体是每抠出一个单词串temp,拼接在原有目标串前面,即dest=temp+' '+dest;
本人采用思路一完成代码,此题虽然不难,但还是错了好几次,主要是特例情况考虑不周,如情况:
s=" "
s=" a "
代码:
#include <iostream>#include<string>using namespace std;class Solution {public:void reverseWords(string &s) {if(!s.empty()){int n=s.size()-1;int high=0;int low=0;bool sign=true;reverse_range(s,0,n);while(high<=n){if(s[high]!=' '){if(high==n){reverse_range(s,low,n);}high++;sign=false;}else{if(sign==false){reverse_range(s,low,high-1);high++;low=high;sign=true;}else{s.erase(high,1);n--;}} }if(s[n]==' '){s.erase(n,1);n--;}}}void reverse_range(string &s,int low,int high){char tmp=NULL;while(low<high){tmp=s[low];s[low]=s[high];s[high]=tmp;low++;high--;}}};void main(){string src=" this is a test ";Solution s;s.reverseWords(src);cout<<src<<endl;getchar();}
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