JBPM4.4 使用非zip方式发布流程 实现流程图加载

JBPM4.4 显示流程图片，需要携带流程图发布；这样大多数是采用打包zip方式来部署流程，太过繁琐；所以我采用如下方式发布流程

RepositoryService repositoryService=  processEngine.getRepositoryService();        NewDeployment deploy= repositoryService.createDeployment();        deploy.addResourceFromClasspath("newSite.jpdl.xml")        .addResourceFromClasspath("newSite.png");

action接收processInstanceId，（一般情况下processInstanceId与ExecutionId相同）得到流程图，并在当前activity上画框，来显示流程走到哪里。

public String showImage(){ProcessInstance processInstance = executionService  .findProcessInstanceById(pid);    String processDefinitionId = processInstance.getProcessDefinitionId();  ProcessDefinition processDefinition = repositoryService  .createProcessDefinitionQuery().processDefinitionId(  processDefinitionId).uniqueResult();    Set<String> activityNames = processInstance.findActiveActivityNames();  BufferedImage image = null;    for (String activityName : activityNames) {      ActivityCoordinates ac = repositoryService.getActivityCoordinates(      processInstance.getProcessDefinitionId(), activityName);        InputStream is = repositoryService.getResourceAsStream(      processDefinition.getDeploymentId(), processDefinition      .getImageResourceName());        image = ImageIO.read(is);      Graphics g = image.getGraphics();      g.setColor(new Color(255, 0, 0));        g.drawRect(ac.getX(), ac.getY(), ac.getWidth(), ac.getHeight());      g.dispose();  }    ByteArrayOutputStream output = new ByteArrayOutputStream();  ImageIO.write(image, "PNG", output);  ByteArrayInputStream input = new ByteArrayInputStream(output  .toByteArray());  this.setInputStream(input);  return SUCCESS;}

structs里面配置result为stream类型，class交给spring处理没有集成的可以修改成原有路径

<action name="processImage" class="processImageAction">      <result type="stream">          <param name="contentType">image/png</param>          <param name="inputName">inputStream</param>      </result>  </action>

jsp页面显示

<img src="processImage.action?pid=<s:property value='id'/>"/>