[LeetCode OJ]Binary Tree Preorder Traversal
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Given a binary tree, return the preorder traversal of its nodes' values.
1
\
2
/
微改一下。
For example:
Given binary tree {1,#,2,3},1
\
2
/
3
return [1,2,3].
先序遍历,把中序的稍
/** * Definition for binary tree * struct TreeNode { * int val; * TreeNode *left; * TreeNode *right; * TreeNode(int x) : val(x), left(NULL), right(NULL) {} * }; */class Solution {public: void inorder(TreeNode *root, vector<int> &v) { if(root == NULL) return; v.push_back(root->val); inorder(root->left,v); inorder(root->right,v); } vector<int> preorderTraversal(TreeNode *root) { vector<int> v; inorder(root, v); return v; }};
微改一下。
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