HDOJ 4497 GCD and LCM

组合数学

GCD and LCM

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65535/65535 K (Java/Others)
Total Submission(s): 451    Accepted Submission(s): 216

Problem Description

Given two positive integers G and L, could you tell me how many solutions of (x, y, z) there are, satisfying that gcd(x, y, z) = G and lcm(x, y, z) = L? 
Note, gcd(x, y, z) means the greatest common divisor of x, y and z, while lcm(x, y, z) means the least common multiple of x, y and z. 
Note 2, (1, 2, 3) and (1, 3, 2) are two different solutions.

 

 

Input

First line comes an integer T (T <= 12), telling the number of test cases. 
The next T lines, each contains two positive 32-bit signed integers, G and L. 
It’s guaranteed that each answer will fit in a 32-bit signed integer.

 

 

Output

For each test case, print one line with the number of solutions satisfying the conditions above.

 

 

Sample Input

2

6 72

7 33

 

 

Sample Output

72

0

 

 

Source

2013 ACM-ICPC吉林通化全国邀请赛——题目重现

 

 

Recommend

liuyiding

 

 

 1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4  5 using namespace std; 6  7 int main() 8 { 9     int t,L,G;10     scanf("%d",&t);11     while(t--)12     {13         scanf("%d%d",&G,&L);14         if(L%G!=0)15         {16             puts("0");17             continue;18         }19         int sk=L/G;20         int pp=2,ans=1,cnt;21         while(sk!=1)22         {23             cnt=0;24             while(sk%pp==0)25             {26                 cnt++;27                 sk/=pp;28             }29             pp++;30             if(cnt!=0)31             {32                 ans*=cnt*6;33             }34         }35         printf("%d\n",ans);36     }37     return 0;38 }