LeetCode OJ 之 Palindrome Number(回文数字)

来源:互联网 发布:标书软件 编辑:程序博客网 时间:2024/06/14 00:14

题目:Determine whether an integer is a palindrome. Do this without extra space.

Some hints:

Could negative integers be palindromes? (ie, -1)

If you are thinking of converting the integer to string, note the restriction of using extra space.

You could also try reversing an integer. However, if you have solved the problem "Reverse Integer", you know that the reversed integer might overflow. How would you handle such case?

There is a more generic way of solving this problem.

bool isPalindrome(int x)     {        //如果x<0,则返回错误        if(x < 0)        return false;                int d = 1;  //除数                //求出首次要除的除数        while (x / d >= 10)             d *= 10;        while (x > 0)         {            int q = x / d;  // x的首位数            int r = x % 10; // x的末位数            if (q != r)                 return false;            x = x % d / 10; //x为去掉首位和末位            d /= 100;   //除数/100,继续判断        }        return true;    }


0 0
原创粉丝点击