hdu2054A == B ?

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A == B ?

Time Limit: 1000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 63987 Accepted Submission(s): 10007

Problem Description

Give you two numbers A and B, if A is equal to B, you should print "YES", or print "NO".

Input

each test case contains two numbers A and B.

Output

for each case, if A is equal to B, you should print "YES", or print "NO".

Sample Input

1 22 23 34 3

Sample Output

NOYESYESNO

这其实是道很水的题，但是我WA好多次，因为想！太！多！

其实这道题只需要注意两点

1.数字很长，必须用字符串保存

2.去掉小数点后面无用的0

如果用字符串保存输入，且能使 10.00和10的输出结果为YES 你就可以A了

该题的测试数据并没有+0与-0 001 与1这样的变态数据，不然考虑的越多，代码就超长了，我也是看了大神的代码才发现~~~

#include <iostream>#include <string>using namespace std;string change(string s){int i,flag(0);for(i = 0; i < s.size(); i++){if(s[i]=='.'){flag = 1;break;}}if(flag){for(i = s.size()-1; s[i] == '0'; i--){s = s.substr(0,s.size()-1);}}if(s[s.size()-1] == '.'){s = s.substr(0,s.size()-1);}return s;}int main(){string a,b;while(cin >> a >> b){a = change(a);b = change(b);if(a == b)cout << "YES" << endl;elsecout << "NO" << endl;}return 0;}

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